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Kinetic and potential energy in SHM

Intermediate

Variation with displacement and time.

K = ½k(A² − x²), U = ½kx². K is maximum at the centre; U at the ends. They are equal at x = ±A/√2.

Worked example

At A/√2, speed is 0.71 v_max.

Common mistake

Each oscillates at twice the SHM frequency.

In more detail

In SHM, kinetic energy is ½mv² and potential energy is ½kx². Their sum is constant, with kinetic energy peaking at equilibrium and potential energy peaking at the extremes.

Real-world uses

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Frequently asked questions

Where is kinetic energy zero?

At the turning points, where the velocity is zero.

Where is potential energy zero?

At equilibrium, where displacement is zero.

Are the kinetic and potential energies ever equal?

Yes. They are equal at a displacement of A divided by the square root of two, where each is half the total energy.

Related topics in Oscillations & SHM

Second's pendulum · Simple pendulum in elevator · Energy in SHM · Average energy over a cycle · Differential equation of SHM · Damped oscillations

← All Oscillations & SHM topics