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Deriving formulas by dimensions

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Use dimensions to find how a quantity depends on others, up to a constant.

Key relationT ∝ √(l/g)

Assume a quantity depends on a product of powers of the relevant variables, then choose the exponents so the dimensions match. This gives the functional form but not the constant.

Worked example

For a pendulum, guess T = k·m^a l^b g^c. Matching [T] gives a = 0, b = ½, c = −½, so T = k√(l/g).

Common mistake

You must include every variable that matters. Leaving one out gives a wrong result without any warning.

In more detail

Dimensional analysis can suggest the form of a formula when you know which quantities it depends on. If the period of a pendulum depends on length and g, then combining them to get a time gives T proportional to sqrt(L/g).

Real-world uses

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Frequently asked questions

Does dimensional analysis give the exact formula?

No. It finds the combination of variables but not the numerical constant, which needs experiment or full theory.

What is the Buckingham pi theorem?

A result stating that a physical relation among n variables can be rewritten using n minus k dimensionless groups, where k is the number of independent dimensions.

How do I find the numerical factor?

Dimensional analysis cannot give it. You need an experiment, a full derivation or a known solution to fix the constant.

Related topics in Measurement & Math Tools

Dimensions of a quantity · Dimensional homogeneity · Checking equations by dimensions · Limitations of dimensional analysis · Dimensionless numbers · Order-of-magnitude estimates

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