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Field on axis of a coil

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Field falls off along the axis.

B = μ₀IR²/(2(R² + x²)^{3/2}) on the axis, maximal at the centre and falling as 1/x³ far away.

Worked example

At x = R it's 35% of the centre value.

Common mistake

Used for Helmholtz coils.

In more detail

On the axis of a coil, the field at distance z from its centre is B = μ0NIR²/(2(R²+z²)^(3/2)). It falls off with distance from the coil.

Real-world uses

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Frequently asked questions

Is the field uniform along the axis?

Only near the centre, where it is nearly constant over a region.

Why does it fall off with z?

Because the coil's field spreads out and points more obliquely away from the centre.

Why does the field fall off along the axis?

Points further from the coil are more remote from its current, so the field decreases as the distance increases.

Related topics in Magnetism & Induction

Biot–Savart law · Field of a long straight wire · Field at centre of a loop · Field of a solenoid · Toroid · Ampere's law

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