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Variation of g with altitude

Intermediate

g decreases as one moves away from Earth.

Key relationg' = g(R/(R+h))²

At height h above the surface g' = g(R/(R + h))² ≈ g(1 − 2h/R) for small h. It decreases slowly.

Worked example

At 400 km (ISS) g' ≈ 8.7 m/s², still 89% of the surface value.

Common mistake

Astronauts are weightless due to free fall, not because gravity vanishes.

In more detail

At height h above the surface, g decreases to g(R/(R+h))², because the distance from Earth's centre increases. For small heights, the decrease is roughly 2h/R.

Real-world uses

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Frequently asked questions

How much does g fall on a high mountain?

On the top of Everest it is about 0.3% smaller than at sea level.

Why does altitude matter for g?

Because it increases the distance from the centre of the Earth, so the pull is weaker.

Does g drop to zero at high altitude?

It falls but never reaches zero. At the height of the International Space Station, g is still about 90 percent of its surface value.

Related topics in Gravitation & Orbits

Universal law of gravitation · Gravitational constant G · Acceleration due to gravity · Variation of g with depth · Effect of Earth's rotation on g · Gravitational field

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