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Gauss's law

Intermediate

Flux through a closed surface equals enclosed charge over ε₀.

Key relation∮E·dA = q/ε₀

The net flux through any closed surface equals the enclosed charge divided by ε₀: ∮E·dA = Q_enc/ε₀. It makes fields of symmetrical charge distributions easy.

Worked example

A sphere with 1 nC enclosed: Φ = 113 N·m²/C.

Common mistake

Only enclosed charges count, but all charges produce the field.

In more detail

Gauss's law states that the total electric flux through a closed surface equals the enclosed charge divided by the permittivity of free space. It is a powerful tool for symmetric charge distributions.

Real-world uses

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Frequently asked questions

Does charge outside the surface matter?

No, only the enclosed charge contributes to the total flux.

When is Gauss's law most useful?

When the charge distribution has symmetry that makes the field constant over a chosen surface.

When is Gauss's law easy to use?

When the charge has symmetry, such as spherical, cylindrical or planar, so the field is constant over the chosen surface.

Related topics in Electrostatics

Torque on a dipole in a field · Potential energy of a dipole · Electric flux · Field of infinite line charge · Field of infinite plane sheet · Field of a charged shell

← All Electrostatics topics