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Motion on an inclined plane

Intermediate

Component of weight along the plane drives motion.

Key relationa = g sinθ

Resolve weight into mg sinθ along the slope and mg cosθ perpendicular. Without friction a = g sinθ; with friction a = g(sinθ − μ cosθ).

Worked example

At 30° frictionless: a = 4.9 m/s².

Common mistake

N = mg cosθ, not mg.

In more detail

On a frictionless incline, the component of weight along the slope, mg sin θ, causes acceleration. The normal force is mg cos θ, perpendicular to the surface.

Real-world uses

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Frequently asked questions

Why does the normal force decrease on a steeper slope?

Because only the component mg cos θ of the weight presses into the surface, and cos θ falls as the angle grows.

Does mass affect acceleration down a frictionless slope?

No. All objects accelerate at g sin θ, so mass cancels.

Why does a steeper slope give more acceleration?

The component of weight along the plane is mg sin θ, which grows as the angle increases toward 90 degrees.

Related topics in Newton's Laws & Forces

Connected bodies · Elevator problems · Pulley systems · Static friction · Kinetic friction · Angle of friction and repose

← All Newton's Laws & Forces topics