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Wheatstone bridge

Intermediate

Balanced when ratios of resistances are equal.

Key relationP/Q = R/S

Four resistors in a diamond with a galvanometer across the middle. When P/Q = R/S no current flows through it, which lets you find an unknown resistance precisely.

Worked example

P = 100, Q = 200, R = 150: S = 300 Ω.

Common mistake

Works because of equal potentials, regardless of the supply voltage.

In more detail

A Wheatstone bridge has four resistors arranged in a diamond with a galvanometer across the middle. When the bridge is balanced, no current flows through the galvanometer, which lets unknown resistances be measured precisely.

Real-world uses

Open the interactive lesson, with simulation and quiz →

Frequently asked questions

What is the balance condition?

R1/R2 equals R3/R4, so the galvanometer reads zero.

Why is it precise?

Because the measurement depends on ratios, not on the absolute voltage.

How do I know the bridge is balanced?

The galvanometer shows zero current, which means the potentials at the two midpoints are equal.

Related topics in Current Electricity & Circuits

Cells in series and parallel · Kirchhoff's current law · Kirchhoff's voltage law · Meter bridge · Potentiometer · Ammeter and voltmeter

← All Current Electricity & Circuits topics